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Solution - Absolute value equations

Exact form: x=-23,0
x=-\frac{2}{3} , 0
Decimal form: x=0.667,0
x=-0.667 , 0

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x1|=|8x+1|
without the absolute value bars:

|x|=|y||5x1|=|8x+1|
x=+y(5x1)=(8x+1)
x=y(5x1)=(8x+1)
+x=y(5x1)=(8x+1)
x=y(5x1)=(8x+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x1|=|8x+1|
x=+y , +x=y(5x1)=(8x+1)
x=y , x=y(5x1)=(8x+1)

2. Solve the two equations for x

11 additional steps

(5x-1)=(8x+1)

Subtract from both sides:

(5x-1)-8x=(8x+1)-8x

Group like terms:

(5x-8x)-1=(8x+1)-8x

Simplify the arithmetic:

-3x-1=(8x+1)-8x

Group like terms:

-3x-1=(8x-8x)+1

Simplify the arithmetic:

3x1=1

Add to both sides:

(-3x-1)+1=1+1

Simplify the arithmetic:

3x=1+1

Simplify the arithmetic:

3x=2

Divide both sides by :

(-3x)-3=2-3

Cancel out the negatives:

3x3=2-3

Simplify the fraction:

x=2-3

Move the negative sign from the denominator to the numerator:

x=-23

9 additional steps

(5x-1)=-(8x+1)

Expand the parentheses:

(5x-1)=-8x-1

Add to both sides:

(5x-1)+8x=(-8x-1)+8x

Group like terms:

(5x+8x)-1=(-8x-1)+8x

Simplify the arithmetic:

13x-1=(-8x-1)+8x

Group like terms:

13x-1=(-8x+8x)-1

Simplify the arithmetic:

13x1=1

Add to both sides:

(13x-1)+1=-1+1

Simplify the arithmetic:

13x=1+1

Simplify the arithmetic:

13x=0

Divide both sides by the coefficient:

x=0

3. List the solutions

x=-23,0
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x1|
y=|8x+1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.