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Solution - Absolute value equations

Exact form: x=8,1011
x=8 , \frac{10}{11}
Decimal form: x=8,0.909
x=8 , 0.909

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x1|=|6x9|
without the absolute value bars:

|x|=|y||5x1|=|6x9|
x=+y(5x1)=(6x9)
x=y(5x1)=(6x9)
+x=y(5x1)=(6x9)
x=y(5x1)=(6x9)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x1|=|6x9|
x=+y , +x=y(5x1)=(6x9)
x=y , x=y(5x1)=(6x9)

2. Solve the two equations for x

10 additional steps

(5x-1)=(6x-9)

Subtract from both sides:

(5x-1)-6x=(6x-9)-6x

Group like terms:

(5x-6x)-1=(6x-9)-6x

Simplify the arithmetic:

-x-1=(6x-9)-6x

Group like terms:

-x-1=(6x-6x)-9

Simplify the arithmetic:

x1=9

Add to both sides:

(-x-1)+1=-9+1

Simplify the arithmetic:

x=9+1

Simplify the arithmetic:

x=8

Multiply both sides by :

-x·-1=-8·-1

Remove the one(s):

x=-8·-1

Simplify the arithmetic:

x=8

10 additional steps

(5x-1)=-(6x-9)

Expand the parentheses:

(5x-1)=-6x+9

Add to both sides:

(5x-1)+6x=(-6x+9)+6x

Group like terms:

(5x+6x)-1=(-6x+9)+6x

Simplify the arithmetic:

11x-1=(-6x+9)+6x

Group like terms:

11x-1=(-6x+6x)+9

Simplify the arithmetic:

11x1=9

Add to both sides:

(11x-1)+1=9+1

Simplify the arithmetic:

11x=9+1

Simplify the arithmetic:

11x=10

Divide both sides by :

(11x)11=1011

Simplify the fraction:

x=1011

3. List the solutions

x=8,1011
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x1|
y=|6x9|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.