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Solution - Absolute value equations

Exact form: x=32,-18
x=\frac{3}{2} , -\frac{1}{8}
Mixed number form: x=112,-18
x=1\frac{1}{2} , -\frac{1}{8}
Decimal form: x=1.5,0.125
x=1.5 , -0.125

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x1|=|3x+2|
without the absolute value bars:

|x|=|y||5x1|=|3x+2|
x=+y(5x1)=(3x+2)
x=y(5x1)=(3x+2)
+x=y(5x1)=(3x+2)
x=y(5x1)=(3x+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x1|=|3x+2|
x=+y , +x=y(5x1)=(3x+2)
x=y , x=y(5x1)=(3x+2)

2. Solve the two equations for x

9 additional steps

(5x-1)=(3x+2)

Subtract from both sides:

(5x-1)-3x=(3x+2)-3x

Group like terms:

(5x-3x)-1=(3x+2)-3x

Simplify the arithmetic:

2x-1=(3x+2)-3x

Group like terms:

2x-1=(3x-3x)+2

Simplify the arithmetic:

2x1=2

Add to both sides:

(2x-1)+1=2+1

Simplify the arithmetic:

2x=2+1

Simplify the arithmetic:

2x=3

Divide both sides by :

(2x)2=32

Simplify the fraction:

x=32

10 additional steps

(5x-1)=-(3x+2)

Expand the parentheses:

(5x-1)=-3x-2

Add to both sides:

(5x-1)+3x=(-3x-2)+3x

Group like terms:

(5x+3x)-1=(-3x-2)+3x

Simplify the arithmetic:

8x-1=(-3x-2)+3x

Group like terms:

8x-1=(-3x+3x)-2

Simplify the arithmetic:

8x1=2

Add to both sides:

(8x-1)+1=-2+1

Simplify the arithmetic:

8x=2+1

Simplify the arithmetic:

8x=1

Divide both sides by :

(8x)8=-18

Simplify the fraction:

x=-18

3. List the solutions

x=32,-18
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x1|
y=|3x+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.