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Solution - Absolute value equations

Exact form: x=97,-73
x=\frac{9}{7} , -\frac{7}{3}
Mixed number form: x=127,-213
x=1\frac{2}{7} , -2\frac{1}{3}
Decimal form: x=1.286,2.333
x=1.286 , -2.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|5x1|+|2x8|=0

Add |2x8| to both sides of the equation:

|5x1|+|2x8||2x8|=|2x8|

Simplify the arithmetic

|5x1|=|2x8|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x1|=|2x8|
without the absolute value bars:

|x|=|y||5x1|=|2x8|
x=+y(5x1)=(2x8)
x=y(5x1)=(2x8)
+x=y(5x1)=(2x8)
x=y(5x1)=(2x8)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x1|=|2x8|
x=+y , +x=y(5x1)=(2x8)
x=y , x=y(5x1)=(2x8)

3. Solve the two equations for x

10 additional steps

(5x-1)=-(2x-8)

Expand the parentheses:

(5x-1)=-2x+8

Add to both sides:

(5x-1)+2x=(-2x+8)+2x

Group like terms:

(5x+2x)-1=(-2x+8)+2x

Simplify the arithmetic:

7x-1=(-2x+8)+2x

Group like terms:

7x-1=(-2x+2x)+8

Simplify the arithmetic:

7x1=8

Add to both sides:

(7x-1)+1=8+1

Simplify the arithmetic:

7x=8+1

Simplify the arithmetic:

7x=9

Divide both sides by :

(7x)7=97

Simplify the fraction:

x=97

10 additional steps

(5x-1)=-(-(2x-8))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(5x-1)=2x-8

Subtract from both sides:

(5x-1)-2x=(2x-8)-2x

Group like terms:

(5x-2x)-1=(2x-8)-2x

Simplify the arithmetic:

3x-1=(2x-8)-2x

Group like terms:

3x-1=(2x-2x)-8

Simplify the arithmetic:

3x1=8

Add to both sides:

(3x-1)+1=-8+1

Simplify the arithmetic:

3x=8+1

Simplify the arithmetic:

3x=7

Divide both sides by :

(3x)3=-73

Simplify the fraction:

x=-73

4. List the solutions

x=97,-73
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|5x1|
y=|2x8|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.