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Solution - Absolute value equations

Exact form: x=18,112
x=\frac{1}{8} , \frac{1}{12}
Decimal form: x=0.125,0.083
x=0.125 , 0.083

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|5x-12|-|x|=0

Add |x| to both sides of the equation:

|5x-12|-|x|+|x|=|x|

Simplify the arithmetic

|5x-12|=|x|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x-12|=|x|
without the absolute value bars:

|x|=|y||5x-12|=|x|
x=+y(5x-12)=(x)
x=-y(5x-12)=(-(x))
+x=y(5x-12)=(x)
-x=y-(5x-12)=(x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x-12|=|x|
x=+y , +x=y(5x-12)=(x)
x=-y , -x=y(5x-12)=(-(x))

3. Solve the two equations for x

13 additional steps

(5x+-12)=x

Subtract from both sides:

(5x+-12)-x=x-x

Group like terms:

(5x-x)+-12=x-x

Simplify the arithmetic:

4x+-12=x-x

Simplify the arithmetic:

4x+-12=0

Add to both sides:

(4x+-12)+12=0+12

Combine the fractions:

4x+(-1+1)2=0+12

Combine the numerators:

4x+02=0+12

Reduce the zero numerator:

4x+0=0+12

Simplify the arithmetic:

4x=0+12

Simplify the arithmetic:

4x=12

Divide both sides by :

(4x)4=(12)4

Simplify the fraction:

x=(12)4

Simplify the arithmetic:

x=1(2·4)

x=18

13 additional steps

(5x+-12)=-x

Add to both sides:

(5x+-12)+x=-x+x

Group like terms:

(5x+x)+-12=-x+x

Simplify the arithmetic:

6x+-12=-x+x

Simplify the arithmetic:

6x+-12=0

Add to both sides:

(6x+-12)+12=0+12

Combine the fractions:

6x+(-1+1)2=0+12

Combine the numerators:

6x+02=0+12

Reduce the zero numerator:

6x+0=0+12

Simplify the arithmetic:

6x=0+12

Simplify the arithmetic:

6x=12

Divide both sides by :

(6x)6=(12)6

Simplify the fraction:

x=(12)6

Simplify the arithmetic:

x=1(2·6)

x=112

4. List the solutions

x=18,112
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|5x-12|
y=|x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.