Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=-32
x=-\frac{3}{2}
Mixed number form: x=-112
x=-1\frac{1}{2}
Decimal form: x=1.5
x=-1.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x+8|=|5x7|
without the absolute value bars:

|x|=|y||5x+8|=|5x7|
x=+y(5x+8)=(5x7)
x=y(5x+8)=(5x7)
+x=y(5x+8)=(5x7)
x=y(5x+8)=(5x7)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x+8|=|5x7|
x=+y , +x=y(5x+8)=(5x7)
x=y , x=y(5x+8)=(5x7)

2. Solve the two equations for x

11 additional steps

(5x+8)=(-5x-7)

Add to both sides:

(5x+8)+5x=(-5x-7)+5x

Group like terms:

(5x+5x)+8=(-5x-7)+5x

Simplify the arithmetic:

10x+8=(-5x-7)+5x

Group like terms:

10x+8=(-5x+5x)-7

Simplify the arithmetic:

10x+8=7

Subtract from both sides:

(10x+8)-8=-7-8

Simplify the arithmetic:

10x=78

Simplify the arithmetic:

10x=15

Divide both sides by :

(10x)10=-1510

Simplify the fraction:

x=-1510

Find the greatest common factor of the numerator and denominator:

x=(-3·5)(2·5)

Factor out and cancel the greatest common factor:

x=-32

6 additional steps

(5x+8)=-(-5x-7)

Expand the parentheses:

(5x+8)=5x+7

Subtract from both sides:

(5x+8)-5x=(5x+7)-5x

Group like terms:

(5x-5x)+8=(5x+7)-5x

Simplify the arithmetic:

8=(5x+7)-5x

Group like terms:

8=(5x-5x)+7

Simplify the arithmetic:

8=7

The statement is false:

8=7

The equation is false so it has no solution.

3. List the solutions

x=-32
(1 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x+8|
y=|5x7|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.