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Solution - Absolute value equations

Exact form: x=-1,-32
x=-1 , -\frac{3}{2}
Mixed number form: x=-1,-112
x=-1 , -1\frac{1}{2}
Decimal form: x=1,1.5
x=-1 , -1.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x+7|=|3x+5|
without the absolute value bars:

|x|=|y||5x+7|=|3x+5|
x=+y(5x+7)=(3x+5)
x=y(5x+7)=(3x+5)
+x=y(5x+7)=(3x+5)
x=y(5x+7)=(3x+5)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x+7|=|3x+5|
x=+y , +x=y(5x+7)=(3x+5)
x=y , x=y(5x+7)=(3x+5)

2. Solve the two equations for x

10 additional steps

(5x+7)=(3x+5)

Subtract from both sides:

(5x+7)-3x=(3x+5)-3x

Group like terms:

(5x-3x)+7=(3x+5)-3x

Simplify the arithmetic:

2x+7=(3x+5)-3x

Group like terms:

2x+7=(3x-3x)+5

Simplify the arithmetic:

2x+7=5

Subtract from both sides:

(2x+7)-7=5-7

Simplify the arithmetic:

2x=57

Simplify the arithmetic:

2x=2

Divide both sides by :

(2x)2=-22

Simplify the fraction:

x=-22

Simplify the fraction:

x=1

12 additional steps

(5x+7)=-(3x+5)

Expand the parentheses:

(5x+7)=-3x-5

Add to both sides:

(5x+7)+3x=(-3x-5)+3x

Group like terms:

(5x+3x)+7=(-3x-5)+3x

Simplify the arithmetic:

8x+7=(-3x-5)+3x

Group like terms:

8x+7=(-3x+3x)-5

Simplify the arithmetic:

8x+7=5

Subtract from both sides:

(8x+7)-7=-5-7

Simplify the arithmetic:

8x=57

Simplify the arithmetic:

8x=12

Divide both sides by :

(8x)8=-128

Simplify the fraction:

x=-128

Find the greatest common factor of the numerator and denominator:

x=(-3·4)(2·4)

Factor out and cancel the greatest common factor:

x=-32

3. List the solutions

x=-1,-32
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x+7|
y=|3x+5|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.