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Solution - Absolute value equations

Exact form: x=-3,-37
x=-3 , -\frac{3}{7}
Decimal form: x=3,0.429
x=-3 , -0.429

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x+6|=|2x3|
without the absolute value bars:

|x|=|y||5x+6|=|2x3|
x=+y(5x+6)=(2x3)
x=y(5x+6)=(2x3)
+x=y(5x+6)=(2x3)
x=y(5x+6)=(2x3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x+6|=|2x3|
x=+y , +x=y(5x+6)=(2x3)
x=y , x=y(5x+6)=(2x3)

2. Solve the two equations for x

11 additional steps

(5x+6)=(2x-3)

Subtract from both sides:

(5x+6)-2x=(2x-3)-2x

Group like terms:

(5x-2x)+6=(2x-3)-2x

Simplify the arithmetic:

3x+6=(2x-3)-2x

Group like terms:

3x+6=(2x-2x)-3

Simplify the arithmetic:

3x+6=3

Subtract from both sides:

(3x+6)-6=-3-6

Simplify the arithmetic:

3x=36

Simplify the arithmetic:

3x=9

Divide both sides by :

(3x)3=-93

Simplify the fraction:

x=-93

Find the greatest common factor of the numerator and denominator:

x=(-3·3)(1·3)

Factor out and cancel the greatest common factor:

x=3

10 additional steps

(5x+6)=-(2x-3)

Expand the parentheses:

(5x+6)=-2x+3

Add to both sides:

(5x+6)+2x=(-2x+3)+2x

Group like terms:

(5x+2x)+6=(-2x+3)+2x

Simplify the arithmetic:

7x+6=(-2x+3)+2x

Group like terms:

7x+6=(-2x+2x)+3

Simplify the arithmetic:

7x+6=3

Subtract from both sides:

(7x+6)-6=3-6

Simplify the arithmetic:

7x=36

Simplify the arithmetic:

7x=3

Divide both sides by :

(7x)7=-37

Simplify the fraction:

x=-37

3. List the solutions

x=-3,-37
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x+6|
y=|2x3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.