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Solution - Absolute value equations

Exact form: x=3,-16
x=3 , -\frac{1}{6}
Decimal form: x=3,0.167
x=3 , -0.167

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x+4|=|7x2|
without the absolute value bars:

|x|=|y||5x+4|=|7x2|
x=+y(5x+4)=(7x2)
x=y(5x+4)=(7x2)
+x=y(5x+4)=(7x2)
x=y(5x+4)=(7x2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x+4|=|7x2|
x=+y , +x=y(5x+4)=(7x2)
x=y , x=y(5x+4)=(7x2)

2. Solve the two equations for x

13 additional steps

(5x+4)=(7x-2)

Subtract from both sides:

(5x+4)-7x=(7x-2)-7x

Group like terms:

(5x-7x)+4=(7x-2)-7x

Simplify the arithmetic:

-2x+4=(7x-2)-7x

Group like terms:

-2x+4=(7x-7x)-2

Simplify the arithmetic:

2x+4=2

Subtract from both sides:

(-2x+4)-4=-2-4

Simplify the arithmetic:

2x=24

Simplify the arithmetic:

2x=6

Divide both sides by :

(-2x)-2=-6-2

Cancel out the negatives:

2x2=-6-2

Simplify the fraction:

x=-6-2

Cancel out the negatives:

x=62

Find the greatest common factor of the numerator and denominator:

x=(3·2)(1·2)

Factor out and cancel the greatest common factor:

x=3

12 additional steps

(5x+4)=-(7x-2)

Expand the parentheses:

(5x+4)=-7x+2

Add to both sides:

(5x+4)+7x=(-7x+2)+7x

Group like terms:

(5x+7x)+4=(-7x+2)+7x

Simplify the arithmetic:

12x+4=(-7x+2)+7x

Group like terms:

12x+4=(-7x+7x)+2

Simplify the arithmetic:

12x+4=2

Subtract from both sides:

(12x+4)-4=2-4

Simplify the arithmetic:

12x=24

Simplify the arithmetic:

12x=2

Divide both sides by :

(12x)12=-212

Simplify the fraction:

x=-212

Find the greatest common factor of the numerator and denominator:

x=(-1·2)(6·2)

Factor out and cancel the greatest common factor:

x=-16

3. List the solutions

x=3,-16
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x+4|
y=|7x2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.