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Solution - Absolute value equations

Exact form: x=-34,-16
x=-\frac{3}{4} , -\frac{1}{6}
Decimal form: x=0.75,0.167
x=-0.75 , -0.167

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x+2|=|x1|
without the absolute value bars:

|x|=|y||5x+2|=|x1|
x=+y(5x+2)=(x1)
x=y(5x+2)=(x1)
+x=y(5x+2)=(x1)
x=y(5x+2)=(x1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x+2|=|x1|
x=+y , +x=y(5x+2)=(x1)
x=y , x=y(5x+2)=(x1)

2. Solve the two equations for x

9 additional steps

(5x+2)=(x-1)

Subtract from both sides:

(5x+2)-x=(x-1)-x

Group like terms:

(5x-x)+2=(x-1)-x

Simplify the arithmetic:

4x+2=(x-1)-x

Group like terms:

4x+2=(x-x)-1

Simplify the arithmetic:

4x+2=1

Subtract from both sides:

(4x+2)-2=-1-2

Simplify the arithmetic:

4x=12

Simplify the arithmetic:

4x=3

Divide both sides by :

(4x)4=-34

Simplify the fraction:

x=-34

10 additional steps

(5x+2)=-(x-1)

Expand the parentheses:

(5x+2)=-x+1

Add to both sides:

(5x+2)+x=(-x+1)+x

Group like terms:

(5x+x)+2=(-x+1)+x

Simplify the arithmetic:

6x+2=(-x+1)+x

Group like terms:

6x+2=(-x+x)+1

Simplify the arithmetic:

6x+2=1

Subtract from both sides:

(6x+2)-2=1-2

Simplify the arithmetic:

6x=12

Simplify the arithmetic:

6x=1

Divide both sides by :

(6x)6=-16

Simplify the fraction:

x=-16

3. List the solutions

x=-34,-16
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x+2|
y=|x1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.