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Solution - Absolute value equations

Exact form: x=13,-313
x=\frac{1}{3} , -\frac{3}{13}
Decimal form: x=0.333,0.231
x=0.333 , -0.231

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x+2|=|8x+1|
without the absolute value bars:

|x|=|y||5x+2|=|8x+1|
x=+y(5x+2)=(8x+1)
x=y(5x+2)=(8x+1)
+x=y(5x+2)=(8x+1)
x=y(5x+2)=(8x+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x+2|=|8x+1|
x=+y , +x=y(5x+2)=(8x+1)
x=y , x=y(5x+2)=(8x+1)

2. Solve the two equations for x

11 additional steps

(5x+2)=(8x+1)

Subtract from both sides:

(5x+2)-8x=(8x+1)-8x

Group like terms:

(5x-8x)+2=(8x+1)-8x

Simplify the arithmetic:

-3x+2=(8x+1)-8x

Group like terms:

-3x+2=(8x-8x)+1

Simplify the arithmetic:

3x+2=1

Subtract from both sides:

(-3x+2)-2=1-2

Simplify the arithmetic:

3x=12

Simplify the arithmetic:

3x=1

Divide both sides by :

(-3x)-3=-1-3

Cancel out the negatives:

3x3=-1-3

Simplify the fraction:

x=-1-3

Cancel out the negatives:

x=13

10 additional steps

(5x+2)=-(8x+1)

Expand the parentheses:

(5x+2)=-8x-1

Add to both sides:

(5x+2)+8x=(-8x-1)+8x

Group like terms:

(5x+8x)+2=(-8x-1)+8x

Simplify the arithmetic:

13x+2=(-8x-1)+8x

Group like terms:

13x+2=(-8x+8x)-1

Simplify the arithmetic:

13x+2=1

Subtract from both sides:

(13x+2)-2=-1-2

Simplify the arithmetic:

13x=12

Simplify the arithmetic:

13x=3

Divide both sides by :

(13x)13=-313

Simplify the fraction:

x=-313

3. List the solutions

x=13,-313
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x+2|
y=|8x+1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.