Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=2,2
x=-2 , -2

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x+10|=|3x+6|
without the absolute value bars:

|x|=|y||5x+10|=|3x+6|
x=+y(5x+10)=(3x+6)
x=y(5x+10)=((3x+6))
+x=y(5x+10)=(3x+6)
x=y(5x+10)=(3x+6)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x+10|=|3x+6|
x=+y , +x=y(5x+10)=(3x+6)
x=y , x=y(5x+10)=((3x+6))

2. Solve the two equations for x

12 additional steps

(5x+10)=-(3x+6)

Expand the parentheses:

(5x+10)=-3x-6

Add to both sides:

(5x+10)+3x=(-3x-6)+3x

Group like terms:

(5x+3x)+10=(-3x-6)+3x

Simplify the arithmetic:

8x+10=(-3x-6)+3x

Group like terms:

8x+10=(-3x+3x)-6

Simplify the arithmetic:

8x+10=6

Subtract from both sides:

(8x+10)-10=-6-10

Simplify the arithmetic:

8x=610

Simplify the arithmetic:

8x=16

Divide both sides by :

(8x)8=-168

Simplify the fraction:

x=-168

Find the greatest common factor of the numerator and denominator:

x=(-2·8)(1·8)

Factor out and cancel the greatest common factor:

x=2

12 additional steps

(5x+10)=-(-(3x+6))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(5x+10)=3x+6

Subtract from both sides:

(5x+10)-3x=(3x+6)-3x

Group like terms:

(5x-3x)+10=(3x+6)-3x

Simplify the arithmetic:

2x+10=(3x+6)-3x

Group like terms:

2x+10=(3x-3x)+6

Simplify the arithmetic:

2x+10=6

Subtract from both sides:

(2x+10)-10=6-10

Simplify the arithmetic:

2x=610

Simplify the arithmetic:

2x=4

Divide both sides by :

(2x)2=-42

Simplify the fraction:

x=-42

Find the greatest common factor of the numerator and denominator:

x=(-2·2)(1·2)

Factor out and cancel the greatest common factor:

x=2

3. List the solutions

x=2,2
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x+10|
y=|3x+6|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.