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Solution - Absolute value equations

Exact form: x=1,113
x=1 , \frac{1}{13}
Decimal form: x=1,0.077
x=1 , 0.077

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x+1|=|8x2|
without the absolute value bars:

|x|=|y||5x+1|=|8x2|
x=+y(5x+1)=(8x2)
x=y(5x+1)=(8x2)
+x=y(5x+1)=(8x2)
x=y(5x+1)=(8x2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x+1|=|8x2|
x=+y , +x=y(5x+1)=(8x2)
x=y , x=y(5x+1)=(8x2)

2. Solve the two equations for x

12 additional steps

(5x+1)=(8x-2)

Subtract from both sides:

(5x+1)-8x=(8x-2)-8x

Group like terms:

(5x-8x)+1=(8x-2)-8x

Simplify the arithmetic:

-3x+1=(8x-2)-8x

Group like terms:

-3x+1=(8x-8x)-2

Simplify the arithmetic:

3x+1=2

Subtract from both sides:

(-3x+1)-1=-2-1

Simplify the arithmetic:

3x=21

Simplify the arithmetic:

3x=3

Divide both sides by :

(-3x)-3=-3-3

Cancel out the negatives:

3x3=-3-3

Simplify the fraction:

x=-3-3

Cancel out the negatives:

x=33

Simplify the fraction:

x=1

10 additional steps

(5x+1)=-(8x-2)

Expand the parentheses:

(5x+1)=-8x+2

Add to both sides:

(5x+1)+8x=(-8x+2)+8x

Group like terms:

(5x+8x)+1=(-8x+2)+8x

Simplify the arithmetic:

13x+1=(-8x+2)+8x

Group like terms:

13x+1=(-8x+8x)+2

Simplify the arithmetic:

13x+1=2

Subtract from both sides:

(13x+1)-1=2-1

Simplify the arithmetic:

13x=21

Simplify the arithmetic:

13x=1

Divide both sides by :

(13x)13=113

Simplify the fraction:

x=113

3. List the solutions

x=1,113
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x+1|
y=|8x2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.