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Solution - Absolute value equations

Exact form: w=3,-14
w=3 , -\frac{1}{4}
Decimal form: w=3,0.25
w=3 , -0.25

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5w2|=|3w+4|
without the absolute value bars:

|x|=|y||5w2|=|3w+4|
x=+y(5w2)=(3w+4)
x=y(5w2)=(3w+4)
+x=y(5w2)=(3w+4)
x=y(5w2)=(3w+4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5w2|=|3w+4|
x=+y , +x=y(5w2)=(3w+4)
x=y , x=y(5w2)=(3w+4)

2. Solve the two equations for w

11 additional steps

(5w-2)=(3w+4)

Subtract from both sides:

(5w-2)-3w=(3w+4)-3w

Group like terms:

(5w-3w)-2=(3w+4)-3w

Simplify the arithmetic:

2w-2=(3w+4)-3w

Group like terms:

2w-2=(3w-3w)+4

Simplify the arithmetic:

2w2=4

Add to both sides:

(2w-2)+2=4+2

Simplify the arithmetic:

2w=4+2

Simplify the arithmetic:

2w=6

Divide both sides by :

(2w)2=62

Simplify the fraction:

w=62

Find the greatest common factor of the numerator and denominator:

w=(3·2)(1·2)

Factor out and cancel the greatest common factor:

w=3

12 additional steps

(5w-2)=-(3w+4)

Expand the parentheses:

(5w-2)=-3w-4

Add to both sides:

(5w-2)+3w=(-3w-4)+3w

Group like terms:

(5w+3w)-2=(-3w-4)+3w

Simplify the arithmetic:

8w-2=(-3w-4)+3w

Group like terms:

8w-2=(-3w+3w)-4

Simplify the arithmetic:

8w2=4

Add to both sides:

(8w-2)+2=-4+2

Simplify the arithmetic:

8w=4+2

Simplify the arithmetic:

8w=2

Divide both sides by :

(8w)8=-28

Simplify the fraction:

w=-28

Find the greatest common factor of the numerator and denominator:

w=(-1·2)(4·2)

Factor out and cancel the greatest common factor:

w=-14

3. List the solutions

w=3,-14
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5w2|
y=|3w+4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.