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Solution - Absolute value equations

Exact form: w=-8,23
w=-8 , \frac{2}{3}
Decimal form: w=8,0.667
w=-8 , 0.667

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5w+1|=|4w7|
without the absolute value bars:

|x|=|y||5w+1|=|4w7|
x=+y(5w+1)=(4w7)
x=y(5w+1)=(4w7)
+x=y(5w+1)=(4w7)
x=y(5w+1)=(4w7)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5w+1|=|4w7|
x=+y , +x=y(5w+1)=(4w7)
x=y , x=y(5w+1)=(4w7)

2. Solve the two equations for w

7 additional steps

(5w+1)=(4w-7)

Subtract from both sides:

(5w+1)-4w=(4w-7)-4w

Group like terms:

(5w-4w)+1=(4w-7)-4w

Simplify the arithmetic:

w+1=(4w-7)-4w

Group like terms:

w+1=(4w-4w)-7

Simplify the arithmetic:

w+1=7

Subtract from both sides:

(w+1)-1=-7-1

Simplify the arithmetic:

w=71

Simplify the arithmetic:

w=8

12 additional steps

(5w+1)=-(4w-7)

Expand the parentheses:

(5w+1)=-4w+7

Add to both sides:

(5w+1)+4w=(-4w+7)+4w

Group like terms:

(5w+4w)+1=(-4w+7)+4w

Simplify the arithmetic:

9w+1=(-4w+7)+4w

Group like terms:

9w+1=(-4w+4w)+7

Simplify the arithmetic:

9w+1=7

Subtract from both sides:

(9w+1)-1=7-1

Simplify the arithmetic:

9w=71

Simplify the arithmetic:

9w=6

Divide both sides by :

(9w)9=69

Simplify the fraction:

w=69

Find the greatest common factor of the numerator and denominator:

w=(2·3)(3·3)

Factor out and cancel the greatest common factor:

w=23

3. List the solutions

w=-8,23
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5w+1|
y=|4w7|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.