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Solution - Absolute value equations

Exact form: s=3,1
s=-3 , 1

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5s+3|=|s9|
without the absolute value bars:

|x|=|y||5s+3|=|s9|
x=+y(5s+3)=(s9)
x=y(5s+3)=(s9)
+x=y(5s+3)=(s9)
x=y(5s+3)=(s9)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5s+3|=|s9|
x=+y , +x=y(5s+3)=(s9)
x=y , x=y(5s+3)=(s9)

2. Solve the two equations for s

11 additional steps

(5s+3)=(s-9)

Subtract from both sides:

(5s+3)-s=(s-9)-s

Group like terms:

(5s-s)+3=(s-9)-s

Simplify the arithmetic:

4s+3=(s-9)-s

Group like terms:

4s+3=(s-s)-9

Simplify the arithmetic:

4s+3=-9

Subtract from both sides:

(4s+3)-3=-9-3

Simplify the arithmetic:

4s=-9-3

Simplify the arithmetic:

4s=-12

Divide both sides by :

(4s)4=-124

Simplify the fraction:

s=-124

Find the greatest common factor of the numerator and denominator:

s=(-3·4)(1·4)

Factor out and cancel the greatest common factor:

s=-3

11 additional steps

(5s+3)=-(s-9)

Expand the parentheses:

(5s+3)=-s+9

Add to both sides:

(5s+3)+s=(-s+9)+s

Group like terms:

(5s+s)+3=(-s+9)+s

Simplify the arithmetic:

6s+3=(-s+9)+s

Group like terms:

6s+3=(-s+s)+9

Simplify the arithmetic:

6s+3=9

Subtract from both sides:

(6s+3)-3=9-3

Simplify the arithmetic:

6s=9-3

Simplify the arithmetic:

6s=6

Divide both sides by :

(6s)6=66

Simplify the fraction:

s=66

Simplify the fraction:

s=1

3. List the solutions

s=3,1
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5s+3|
y=|s9|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.