Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: p=-4,-109
p=-4 , -\frac{10}{9}
Mixed number form: p=-4,-119
p=-4 , -1\frac{1}{9}
Decimal form: p=4,1.111
p=-4 , -1.111

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5p+7|=|4p+3|
without the absolute value bars:

|x|=|y||5p+7|=|4p+3|
x=+y(5p+7)=(4p+3)
x=y(5p+7)=(4p+3)
+x=y(5p+7)=(4p+3)
x=y(5p+7)=(4p+3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5p+7|=|4p+3|
x=+y , +x=y(5p+7)=(4p+3)
x=y , x=y(5p+7)=(4p+3)

2. Solve the two equations for p

7 additional steps

(5p+7)=(4p+3)

Subtract from both sides:

(5p+7)-4p=(4p+3)-4p

Group like terms:

(5p-4p)+7=(4p+3)-4p

Simplify the arithmetic:

p+7=(4p+3)-4p

Group like terms:

p+7=(4p-4p)+3

Simplify the arithmetic:

p+7=3

Subtract from both sides:

(p+7)-7=3-7

Simplify the arithmetic:

p=37

Simplify the arithmetic:

p=4

10 additional steps

(5p+7)=-(4p+3)

Expand the parentheses:

(5p+7)=-4p-3

Add to both sides:

(5p+7)+4p=(-4p-3)+4p

Group like terms:

(5p+4p)+7=(-4p-3)+4p

Simplify the arithmetic:

9p+7=(-4p-3)+4p

Group like terms:

9p+7=(-4p+4p)-3

Simplify the arithmetic:

9p+7=3

Subtract from both sides:

(9p+7)-7=-3-7

Simplify the arithmetic:

9p=37

Simplify the arithmetic:

9p=10

Divide both sides by :

(9p)9=-109

Simplify the fraction:

p=-109

3. List the solutions

p=-4,-109
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5p+7|
y=|4p+3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.