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Solution - Absolute value equations

Exact form: k=23,213
k=\frac{2}{3} , \frac{2}{13}
Decimal form: k=0.667,0.154
k=0.667 , 0.154

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5k|=2|4k1|
without the absolute value bars:

|x|=|y||5k|=2|4k1|
x=+y(5k)=2(4k1)
x=y(5k)=2((4k1))
+x=y(5k)=2(4k1)
x=y(5k)=2(4k1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5k|=2|4k1|
x=+y , +x=y(5k)=2(4k1)
x=y , x=y(5k)=2((4k1))

2. Solve the two equations for k

10 additional steps

5k=2·(4k-1)

Expand the parentheses:

5k=2·4k+2·-1

Multiply the coefficients:

5k=8k+2·-1

Simplify the arithmetic:

5k=8k2

Subtract from both sides:

(5k)-8k=(8k-2)-8k

Simplify the arithmetic:

-3k=(8k-2)-8k

Group like terms:

-3k=(8k-8k)-2

Simplify the arithmetic:

3k=2

Divide both sides by :

(-3k)-3=-2-3

Cancel out the negatives:

3k3=-2-3

Simplify the fraction:

k=-2-3

Cancel out the negatives:

k=23

9 additional steps

5k=2·(-(4k-1))

Expand the parentheses:

5k=2·(-4k+1)

Expand the parentheses:

5k=2·-4k+2·1

Multiply the coefficients:

5k=-8k+2·1

Simplify the arithmetic:

5k=8k+2

Add to both sides:

(5k)+8k=(-8k+2)+8k

Simplify the arithmetic:

13k=(-8k+2)+8k

Group like terms:

13k=(-8k+8k)+2

Simplify the arithmetic:

13k=2

Divide both sides by :

(13k)13=213

Simplify the fraction:

k=213

3. List the solutions

k=23,213
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5k|
y=2|4k1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.