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Solution - Absolute value equations

Exact form: a=-2,1211
a=-2 , \frac{12}{11}
Mixed number form: a=-2,1111
a=-2 , 1\frac{1}{11}
Decimal form: a=2,1.091
a=-2 , 1.091

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5a7|=|6a5|
without the absolute value bars:

|x|=|y||5a7|=|6a5|
x=+y(5a7)=(6a5)
x=y(5a7)=(6a5)
+x=y(5a7)=(6a5)
x=y(5a7)=(6a5)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5a7|=|6a5|
x=+y , +x=y(5a7)=(6a5)
x=y , x=y(5a7)=(6a5)

2. Solve the two equations for a

10 additional steps

(5a-7)=(6a-5)

Subtract from both sides:

(5a-7)-6a=(6a-5)-6a

Group like terms:

(5a-6a)-7=(6a-5)-6a

Simplify the arithmetic:

-a-7=(6a-5)-6a

Group like terms:

-a-7=(6a-6a)-5

Simplify the arithmetic:

a7=5

Add to both sides:

(-a-7)+7=-5+7

Simplify the arithmetic:

a=5+7

Simplify the arithmetic:

a=2

Multiply both sides by :

-a·-1=2·-1

Remove the one(s):

a=2·-1

Simplify the arithmetic:

a=2

10 additional steps

(5a-7)=-(6a-5)

Expand the parentheses:

(5a-7)=-6a+5

Add to both sides:

(5a-7)+6a=(-6a+5)+6a

Group like terms:

(5a+6a)-7=(-6a+5)+6a

Simplify the arithmetic:

11a-7=(-6a+5)+6a

Group like terms:

11a-7=(-6a+6a)+5

Simplify the arithmetic:

11a7=5

Add to both sides:

(11a-7)+7=5+7

Simplify the arithmetic:

11a=5+7

Simplify the arithmetic:

11a=12

Divide both sides by :

(11a)11=1211

Simplify the fraction:

a=1211

3. List the solutions

a=-2,1211
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5a7|
y=|6a5|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.