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Solution - Absolute value equations

Exact form:

a = \frac{3}{4}, \frac{1}{2}

a=\frac{3}{4} , \frac{1}{2}

Decimal form:

a = 0.75, 0.5

a=0.75 , 0.5

See steps

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
$| x | = | y |$ → $x = \pm y$ and $| x | = | y |$ → $\pm x = y$
to write all four options of the equation
$| 5 a - 3 | = | a |$
without the absolute value bars:

$\| x \| = \| y \|$	$\| 5 a - 3 \| = \| a \|$
$x = + y$	$(5 a - 3) = (a)$
$x = - y$	$(5 a - 3) = - (a)$
$+ x = y$	$(5 a - 3) = (a)$
$- x = y$	$- (5 a - 3) = (a)$

When simplified, equations $x = + y$ and $+ x = y$ are the same and equations $x = - y$ and $- x = y$ are the same, so we end up with only 2 equations:

$\| x \| = \| y \|$	$\| 5 a - 3 \| = \| a \|$
$x = + y$ , $+ x = y$	$(5 a - 3) = (a)$
$x = - y$ , $- x = y$	$(5 a - 3) = - (a)$

2. Solve the two equations for a

8 additional steps

$(5 a - 3) = a$

Subtract from both sides:

$(5 a - 3) - a = a - a$

Group like terms:

$(5 a - a) - 3 = a - a$

Simplify the arithmetic:

$4 a - 3 = a - a$

Simplify the arithmetic:

$4 a - 3 = 0$

Add to both sides:

$(4 a - 3) + 3 = 0 + 3$

Simplify the arithmetic:

$4 a = 0 + 3$

Simplify the arithmetic:

$4 a = 3$

Divide both sides by :

$\frac{(4 a)}{4} = \frac{3}{4}$

Simplify the fraction:

$a = \frac{3}{4}$

10 additional steps

$(5 a - 3) = - a$

Add to both sides:

$(5 a - 3) + a = - a + a$

Group like terms:

$(5 a + a) - 3 = - a + a$

Simplify the arithmetic:

$6 a - 3 = - a + a$

Simplify the arithmetic:

$6 a - 3 = 0$

Add to both sides:

$(6 a - 3) + 3 = 0 + 3$

Simplify the arithmetic:

$6 a = 0 + 3$

Simplify the arithmetic:

$6 a = 3$

Divide both sides by :

$\frac{(6 a)}{6} = \frac{3}{6}$

Simplify the fraction:

$a = \frac{3}{6}$

Find the greatest common factor of the numerator and denominator:

$a = \frac{(1 \cdot 3)}{(2 \cdot 3)}$

Factor out and cancel the greatest common factor:

$a = \frac{1}{2}$

3. List the solutions

$a = \frac{3}{4}, \frac{1}{2}$
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
$y = | 5 a - 3 |$
$y = | a |$
The equation is true where the two lines cross.

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Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for a

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for a

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

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