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Solution - Absolute value equations

Exact form: a=12,411
a=12 , \frac{4}{11}
Decimal form: a=12,0.364
a=12 , 0.364

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5a+4|=|6a8|
without the absolute value bars:

|x|=|y||5a+4|=|6a8|
x=+y(5a+4)=(6a8)
x=y(5a+4)=(6a8)
+x=y(5a+4)=(6a8)
x=y(5a+4)=(6a8)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5a+4|=|6a8|
x=+y , +x=y(5a+4)=(6a8)
x=y , x=y(5a+4)=(6a8)

2. Solve the two equations for a

10 additional steps

(5a+4)=(6a-8)

Subtract from both sides:

(5a+4)-6a=(6a-8)-6a

Group like terms:

(5a-6a)+4=(6a-8)-6a

Simplify the arithmetic:

-a+4=(6a-8)-6a

Group like terms:

-a+4=(6a-6a)-8

Simplify the arithmetic:

a+4=8

Subtract from both sides:

(-a+4)-4=-8-4

Simplify the arithmetic:

a=84

Simplify the arithmetic:

a=12

Multiply both sides by :

-a·-1=-12·-1

Remove the one(s):

a=-12·-1

Simplify the arithmetic:

a=12

10 additional steps

(5a+4)=-(6a-8)

Expand the parentheses:

(5a+4)=-6a+8

Add to both sides:

(5a+4)+6a=(-6a+8)+6a

Group like terms:

(5a+6a)+4=(-6a+8)+6a

Simplify the arithmetic:

11a+4=(-6a+8)+6a

Group like terms:

11a+4=(-6a+6a)+8

Simplify the arithmetic:

11a+4=8

Subtract from both sides:

(11a+4)-4=8-4

Simplify the arithmetic:

11a=84

Simplify the arithmetic:

11a=4

Divide both sides by :

(11a)11=411

Simplify the fraction:

a=411

3. List the solutions

a=12,411
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5a+4|
y=|6a8|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.