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Solution - Absolute value equations

Exact form: x=-43,65
x=-\frac{4}{3} , \frac{6}{5}
Mixed number form: x=-113,115
x=-1\frac{1}{3} , 1\frac{1}{5}
Decimal form: x=1.333,1.2
x=-1.333 , 1.2

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x+5|=|4x+1|
without the absolute value bars:

|x|=|y||x+5|=|4x+1|
x=+y(x+5)=(4x+1)
x=y(x+5)=(4x+1)
+x=y(x+5)=(4x+1)
x=y(x+5)=(4x+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x+5|=|4x+1|
x=+y , +x=y(x+5)=(4x+1)
x=y , x=y(x+5)=(4x+1)

2. Solve the two equations for x

9 additional steps

(-x+5)=(-4x+1)

Add to both sides:

(-x+5)+4x=(-4x+1)+4x

Group like terms:

(-x+4x)+5=(-4x+1)+4x

Simplify the arithmetic:

3x+5=(-4x+1)+4x

Group like terms:

3x+5=(-4x+4x)+1

Simplify the arithmetic:

3x+5=1

Subtract from both sides:

(3x+5)-5=1-5

Simplify the arithmetic:

3x=15

Simplify the arithmetic:

3x=4

Divide both sides by :

(3x)3=-43

Simplify the fraction:

x=-43

12 additional steps

(-x+5)=-(-4x+1)

Expand the parentheses:

(-x+5)=4x-1

Subtract from both sides:

(-x+5)-4x=(4x-1)-4x

Group like terms:

(-x-4x)+5=(4x-1)-4x

Simplify the arithmetic:

-5x+5=(4x-1)-4x

Group like terms:

-5x+5=(4x-4x)-1

Simplify the arithmetic:

5x+5=1

Subtract from both sides:

(-5x+5)-5=-1-5

Simplify the arithmetic:

5x=15

Simplify the arithmetic:

5x=6

Divide both sides by :

(-5x)-5=-6-5

Cancel out the negatives:

5x5=-6-5

Simplify the fraction:

x=-6-5

Cancel out the negatives:

x=65

3. List the solutions

x=-43,65
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x+5|
y=|4x+1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.