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Solution - Absolute value equations

Exact form: x=25,-12
x=\frac{2}{5} , -12
Decimal form: x=0.4,12
x=0.4 , -12

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x+5|=|2x+7|
without the absolute value bars:

|x|=|y||3x+5|=|2x+7|
x=+y(3x+5)=(2x+7)
x=y(3x+5)=(2x+7)
+x=y(3x+5)=(2x+7)
x=y(3x+5)=(2x+7)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x+5|=|2x+7|
x=+y , +x=y(3x+5)=(2x+7)
x=y , x=y(3x+5)=(2x+7)

2. Solve the two equations for x

9 additional steps

(3x+5)=(-2x+7)

Add to both sides:

(3x+5)+2x=(-2x+7)+2x

Group like terms:

(3x+2x)+5=(-2x+7)+2x

Simplify the arithmetic:

5x+5=(-2x+7)+2x

Group like terms:

5x+5=(-2x+2x)+7

Simplify the arithmetic:

5x+5=7

Subtract from both sides:

(5x+5)-5=7-5

Simplify the arithmetic:

5x=75

Simplify the arithmetic:

5x=2

Divide both sides by :

(5x)5=25

Simplify the fraction:

x=25

8 additional steps

(3x+5)=-(-2x+7)

Expand the parentheses:

(3x+5)=2x-7

Subtract from both sides:

(3x+5)-2x=(2x-7)-2x

Group like terms:

(3x-2x)+5=(2x-7)-2x

Simplify the arithmetic:

x+5=(2x-7)-2x

Group like terms:

x+5=(2x-2x)-7

Simplify the arithmetic:

x+5=7

Subtract from both sides:

(x+5)-5=-7-5

Simplify the arithmetic:

x=75

Simplify the arithmetic:

x=12

3. List the solutions

x=25,-12
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x+5|
y=|2x+7|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.