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Solution - Absolute value equations

Exact form:

y = 6

y=6

See steps

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
$| x | = | y |$ → $x = \pm y$ and $| x | = | y |$ → $\pm x = y$
to write all four options of the equation
$| 4 y - 33 | = | - 4 y + 15 |$
without the absolute value bars:

$\| x \| = \| y \|$	$\| 4 y - 33 \| = \| - 4 y + 15 \|$
$x = + y$	$(4 y - 33) = (- 4 y + 15)$
$x = - y$	$(4 y - 33) = - (- 4 y + 15)$
$+ x = y$	$(4 y - 33) = (- 4 y + 15)$
$- x = y$	$- (4 y - 33) = (- 4 y + 15)$

When simplified, equations $x = + y$ and $+ x = y$ are the same and equations $x = - y$ and $- x = y$ are the same, so we end up with only 2 equations:

$\| x \| = \| y \|$	$\| 4 y - 33 \| = \| - 4 y + 15 \|$
$x = + y$ , $+ x = y$	$(4 y - 33) = (- 4 y + 15)$
$x = - y$ , $- x = y$	$(4 y - 33) = - (- 4 y + 15)$

2. Solve the two equations for y

11 additional steps

$(4 y - 33) = (- 4 y + 15)$

Add to both sides:

$(4 y - 33) + 4 y = (- 4 y + 15) + 4 y$

Group like terms:

$(4 y + 4 y) - 33 = (- 4 y + 15) + 4 y$

Simplify the arithmetic:

$8 y - 33 = (- 4 y + 15) + 4 y$

Group like terms:

$8 y - 33 = (- 4 y + 4 y) + 15$

Simplify the arithmetic:

$8 y - 33 = 15$

Add to both sides:

$(8 y - 33) + 33 = 15 + 33$

Simplify the arithmetic:

$8 y = 15 + 33$

Simplify the arithmetic:

$8 y = 48$

Divide both sides by :

$\frac{(8 y)}{8} = \frac{48}{8}$

Simplify the fraction:

$y = \frac{48}{8}$

Find the greatest common factor of the numerator and denominator:

$y = \frac{(6 \cdot 8)}{(1 \cdot 8)}$

Factor out and cancel the greatest common factor:

$y = 6$

6 additional steps

$(4 y - 33) = - (- 4 y + 15)$

Expand the parentheses:

$(4 y - 33) = 4 y - 15$

Subtract from both sides:

$(4 y - 33) - 4 y = (4 y - 15) - 4 y$

Group like terms:

$(4 y - 4 y) - 33 = (4 y - 15) - 4 y$

Simplify the arithmetic:

$- 33 = (4 y - 15) - 4 y$

Group like terms:

$- 33 = (4 y - 4 y) - 15$

Simplify the arithmetic:

$- 33 = - 15$

The statement is false:

$- 33 = - 15$

The equation is false so it has no solution.

3. List the solutions

$y = 6$
(1 solution(s))

4. Graph

Each line represents the function of one side of the equation:
$y = | 4 y - 33 |$
$y = | - 4 y + 15 |$
The equation is true where the two lines cross.

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Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for y

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for y

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

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