Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=-32,12
x=-\frac{3}{2} , \frac{1}{2}
Mixed number form: x=-112,12
x=-1\frac{1}{2} , \frac{1}{2}
Decimal form: x=1.5,0.5
x=-1.5 , 0.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4x|=|2x3|
without the absolute value bars:

|x|=|y||4x|=|2x3|
x=+y(4x)=(2x3)
x=y(4x)=(2x3)
+x=y(4x)=(2x3)
x=y(4x)=(2x3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4x|=|2x3|
x=+y , +x=y(4x)=(2x3)
x=y , x=y(4x)=(2x3)

2. Solve the two equations for x

5 additional steps

4x=(2x-3)

Subtract from both sides:

(4x)-2x=(2x-3)-2x

Simplify the arithmetic:

2x=(2x-3)-2x

Group like terms:

2x=(2x-2x)-3

Simplify the arithmetic:

2x=3

Divide both sides by :

(2x)2=-32

Simplify the fraction:

x=-32

8 additional steps

4x=-(2x-3)

Expand the parentheses:

4x=2x+3

Add to both sides:

(4x)+2x=(-2x+3)+2x

Simplify the arithmetic:

6x=(-2x+3)+2x

Group like terms:

6x=(-2x+2x)+3

Simplify the arithmetic:

6x=3

Divide both sides by :

(6x)6=36

Simplify the fraction:

x=36

Find the greatest common factor of the numerator and denominator:

x=(1·3)(2·3)

Factor out and cancel the greatest common factor:

x=12

3. List the solutions

x=-32,12
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4x|
y=|2x3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.