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Solution - Absolute value equations

Exact form: x=2,125
x=2 , \frac{12}{5}
Mixed number form: x=2,225
x=2 , 2\frac{2}{5}
Decimal form: x=2,2.4
x=2 , 2.4

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4x9|=|x3|
without the absolute value bars:

|x|=|y||4x9|=|x3|
x=+y(4x9)=(x3)
x=y(4x9)=(x3)
+x=y(4x9)=(x3)
x=y(4x9)=(x3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4x9|=|x3|
x=+y , +x=y(4x9)=(x3)
x=y , x=y(4x9)=(x3)

2. Solve the two equations for x

11 additional steps

(4x-9)=(x-3)

Subtract from both sides:

(4x-9)-x=(x-3)-x

Group like terms:

(4x-x)-9=(x-3)-x

Simplify the arithmetic:

3x-9=(x-3)-x

Group like terms:

3x-9=(x-x)-3

Simplify the arithmetic:

3x9=3

Add to both sides:

(3x-9)+9=-3+9

Simplify the arithmetic:

3x=3+9

Simplify the arithmetic:

3x=6

Divide both sides by :

(3x)3=63

Simplify the fraction:

x=63

Find the greatest common factor of the numerator and denominator:

x=(2·3)(1·3)

Factor out and cancel the greatest common factor:

x=2

10 additional steps

(4x-9)=-(x-3)

Expand the parentheses:

(4x-9)=-x+3

Add to both sides:

(4x-9)+x=(-x+3)+x

Group like terms:

(4x+x)-9=(-x+3)+x

Simplify the arithmetic:

5x-9=(-x+3)+x

Group like terms:

5x-9=(-x+x)+3

Simplify the arithmetic:

5x9=3

Add to both sides:

(5x-9)+9=3+9

Simplify the arithmetic:

5x=3+9

Simplify the arithmetic:

5x=12

Divide both sides by :

(5x)5=125

Simplify the fraction:

x=125

3. List the solutions

x=2,125
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4x9|
y=|x3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.