Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=-113,711
x=-\frac{11}{3} , \frac{7}{11}
Mixed number form: x=-323,711
x=-3\frac{2}{3} , \frac{7}{11}
Decimal form: x=3.667,0.636
x=-3.667 , 0.636

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4x9|=|7x+2|
without the absolute value bars:

|x|=|y||4x9|=|7x+2|
x=+y(4x9)=(7x+2)
x=y(4x9)=(7x+2)
+x=y(4x9)=(7x+2)
x=y(4x9)=(7x+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4x9|=|7x+2|
x=+y , +x=y(4x9)=(7x+2)
x=y , x=y(4x9)=(7x+2)

2. Solve the two equations for x

11 additional steps

(4x-9)=(7x+2)

Subtract from both sides:

(4x-9)-7x=(7x+2)-7x

Group like terms:

(4x-7x)-9=(7x+2)-7x

Simplify the arithmetic:

-3x-9=(7x+2)-7x

Group like terms:

-3x-9=(7x-7x)+2

Simplify the arithmetic:

3x9=2

Add to both sides:

(-3x-9)+9=2+9

Simplify the arithmetic:

3x=2+9

Simplify the arithmetic:

3x=11

Divide both sides by :

(-3x)-3=11-3

Cancel out the negatives:

3x3=11-3

Simplify the fraction:

x=11-3

Move the negative sign from the denominator to the numerator:

x=-113

10 additional steps

(4x-9)=-(7x+2)

Expand the parentheses:

(4x-9)=-7x-2

Add to both sides:

(4x-9)+7x=(-7x-2)+7x

Group like terms:

(4x+7x)-9=(-7x-2)+7x

Simplify the arithmetic:

11x-9=(-7x-2)+7x

Group like terms:

11x-9=(-7x+7x)-2

Simplify the arithmetic:

11x9=2

Add to both sides:

(11x-9)+9=-2+9

Simplify the arithmetic:

11x=2+9

Simplify the arithmetic:

11x=7

Divide both sides by :

(11x)11=711

Simplify the fraction:

x=711

3. List the solutions

x=-113,711
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4x9|
y=|7x+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.