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Solution - Absolute value equations

Exact form: x=125,43
x=\frac{12}{5} , \frac{4}{3}
Mixed number form: x=225,113
x=2\frac{2}{5} , 1\frac{1}{3}
Decimal form: x=2.4,1.333
x=2.4 , 1.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|4x8|+|x4|=0

Add |x4| to both sides of the equation:

|4x8|+|x4||x4|=|x4|

Simplify the arithmetic

|4x8|=|x4|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4x8|=|x4|
without the absolute value bars:

|x|=|y||4x8|=|x4|
x=+y(4x8)=(x4)
x=y(4x8)=(x4)
+x=y(4x8)=(x4)
x=y(4x8)=(x4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4x8|=|x4|
x=+y , +x=y(4x8)=(x4)
x=y , x=y(4x8)=(x4)

3. Solve the two equations for x

10 additional steps

(4x-8)=-(x-4)

Expand the parentheses:

(4x-8)=-x+4

Add to both sides:

(4x-8)+x=(-x+4)+x

Group like terms:

(4x+x)-8=(-x+4)+x

Simplify the arithmetic:

5x-8=(-x+4)+x

Group like terms:

5x-8=(-x+x)+4

Simplify the arithmetic:

5x8=4

Add to both sides:

(5x-8)+8=4+8

Simplify the arithmetic:

5x=4+8

Simplify the arithmetic:

5x=12

Divide both sides by :

(5x)5=125

Simplify the fraction:

x=125

10 additional steps

(4x-8)=-(-(x-4))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(4x-8)=x-4

Subtract from both sides:

(4x-8)-x=(x-4)-x

Group like terms:

(4x-x)-8=(x-4)-x

Simplify the arithmetic:

3x-8=(x-4)-x

Group like terms:

3x-8=(x-x)-4

Simplify the arithmetic:

3x8=4

Add to both sides:

(3x-8)+8=-4+8

Simplify the arithmetic:

3x=4+8

Simplify the arithmetic:

3x=4

Divide both sides by :

(3x)3=43

Simplify the fraction:

x=43

4. List the solutions

x=125,43
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|4x8|
y=|x4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.