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Solution - Absolute value equations

Exact form: x=5,1
x=5 , -1

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4x5|=|x+10|
without the absolute value bars:

|x|=|y||4x5|=|x+10|
x=+y(4x5)=(x+10)
x=y(4x5)=(x+10)
+x=y(4x5)=(x+10)
x=y(4x5)=(x+10)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4x5|=|x+10|
x=+y , +x=y(4x5)=(x+10)
x=y , x=y(4x5)=(x+10)

2. Solve the two equations for x

11 additional steps

(4x-5)=(x+10)

Subtract from both sides:

(4x-5)-x=(x+10)-x

Group like terms:

(4x-x)-5=(x+10)-x

Simplify the arithmetic:

3x-5=(x+10)-x

Group like terms:

3x-5=(x-x)+10

Simplify the arithmetic:

3x5=10

Add to both sides:

(3x-5)+5=10+5

Simplify the arithmetic:

3x=10+5

Simplify the arithmetic:

3x=15

Divide both sides by :

(3x)3=153

Simplify the fraction:

x=153

Find the greatest common factor of the numerator and denominator:

x=(5·3)(1·3)

Factor out and cancel the greatest common factor:

x=5

11 additional steps

(4x-5)=-(x+10)

Expand the parentheses:

(4x-5)=-x-10

Add to both sides:

(4x-5)+x=(-x-10)+x

Group like terms:

(4x+x)-5=(-x-10)+x

Simplify the arithmetic:

5x-5=(-x-10)+x

Group like terms:

5x-5=(-x+x)-10

Simplify the arithmetic:

5x5=10

Add to both sides:

(5x-5)+5=-10+5

Simplify the arithmetic:

5x=10+5

Simplify the arithmetic:

5x=5

Divide both sides by :

(5x)5=-55

Simplify the fraction:

x=-55

Simplify the fraction:

x=1

3. List the solutions

x=5,1
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4x5|
y=|x+10|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.