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Solution - Absolute value equations

Exact form: x=73,-2
x=\frac{7}{3} , -2
Mixed number form: x=213,-2
x=2\frac{1}{3} , -2
Decimal form: x=2.333,2
x=2.333 , -2

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4x5|=|2x+9|
without the absolute value bars:

|x|=|y||4x5|=|2x+9|
x=+y(4x5)=(2x+9)
x=y(4x5)=(2x+9)
+x=y(4x5)=(2x+9)
x=y(4x5)=(2x+9)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4x5|=|2x+9|
x=+y , +x=y(4x5)=(2x+9)
x=y , x=y(4x5)=(2x+9)

2. Solve the two equations for x

11 additional steps

(4x-5)=(-2x+9)

Add to both sides:

(4x-5)+2x=(-2x+9)+2x

Group like terms:

(4x+2x)-5=(-2x+9)+2x

Simplify the arithmetic:

6x-5=(-2x+9)+2x

Group like terms:

6x-5=(-2x+2x)+9

Simplify the arithmetic:

6x5=9

Add to both sides:

(6x-5)+5=9+5

Simplify the arithmetic:

6x=9+5

Simplify the arithmetic:

6x=14

Divide both sides by :

(6x)6=146

Simplify the fraction:

x=146

Find the greatest common factor of the numerator and denominator:

x=(7·2)(3·2)

Factor out and cancel the greatest common factor:

x=73

12 additional steps

(4x-5)=-(-2x+9)

Expand the parentheses:

(4x-5)=2x-9

Subtract from both sides:

(4x-5)-2x=(2x-9)-2x

Group like terms:

(4x-2x)-5=(2x-9)-2x

Simplify the arithmetic:

2x-5=(2x-9)-2x

Group like terms:

2x-5=(2x-2x)-9

Simplify the arithmetic:

2x5=9

Add to both sides:

(2x-5)+5=-9+5

Simplify the arithmetic:

2x=9+5

Simplify the arithmetic:

2x=4

Divide both sides by :

(2x)2=-42

Simplify the fraction:

x=-42

Find the greatest common factor of the numerator and denominator:

x=(-2·2)(1·2)

Factor out and cancel the greatest common factor:

x=2

3. List the solutions

x=73,-2
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4x5|
y=|2x+9|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.