Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=-165,-813
x=-\frac{16}{5} , -\frac{8}{13}
Mixed number form: x=-315,-813
x=-3\frac{1}{5} , -\frac{8}{13}
Decimal form: x=3.2,0.615
x=-3.2 , -0.615

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4x4|=|9x+12|
without the absolute value bars:

|x|=|y||4x4|=|9x+12|
x=+y(4x4)=(9x+12)
x=y(4x4)=(9x+12)
+x=y(4x4)=(9x+12)
x=y(4x4)=(9x+12)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4x4|=|9x+12|
x=+y , +x=y(4x4)=(9x+12)
x=y , x=y(4x4)=(9x+12)

2. Solve the two equations for x

11 additional steps

(4x-4)=(9x+12)

Subtract from both sides:

(4x-4)-9x=(9x+12)-9x

Group like terms:

(4x-9x)-4=(9x+12)-9x

Simplify the arithmetic:

-5x-4=(9x+12)-9x

Group like terms:

-5x-4=(9x-9x)+12

Simplify the arithmetic:

5x4=12

Add to both sides:

(-5x-4)+4=12+4

Simplify the arithmetic:

5x=12+4

Simplify the arithmetic:

5x=16

Divide both sides by :

(-5x)-5=16-5

Cancel out the negatives:

5x5=16-5

Simplify the fraction:

x=16-5

Move the negative sign from the denominator to the numerator:

x=-165

10 additional steps

(4x-4)=-(9x+12)

Expand the parentheses:

(4x-4)=-9x-12

Add to both sides:

(4x-4)+9x=(-9x-12)+9x

Group like terms:

(4x+9x)-4=(-9x-12)+9x

Simplify the arithmetic:

13x-4=(-9x-12)+9x

Group like terms:

13x-4=(-9x+9x)-12

Simplify the arithmetic:

13x4=12

Add to both sides:

(13x-4)+4=-12+4

Simplify the arithmetic:

13x=12+4

Simplify the arithmetic:

13x=8

Divide both sides by :

(13x)13=-813

Simplify the fraction:

x=-813

3. List the solutions

x=-165,-813
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4x4|
y=|9x+12|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.