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Solution - Absolute value equations

Exact form: x=4,-65
x=4 , -\frac{6}{5}
Mixed number form: x=4,-115
x=4 , -1\frac{1}{5}
Decimal form: x=4,1.2
x=4 , -1.2

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4x3|=|x+9|
without the absolute value bars:

|x|=|y||4x3|=|x+9|
x=+y(4x3)=(x+9)
x=y(4x3)=(x+9)
+x=y(4x3)=(x+9)
x=y(4x3)=(x+9)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4x3|=|x+9|
x=+y , +x=y(4x3)=(x+9)
x=y , x=y(4x3)=(x+9)

2. Solve the two equations for x

11 additional steps

(4x-3)=(x+9)

Subtract from both sides:

(4x-3)-x=(x+9)-x

Group like terms:

(4x-x)-3=(x+9)-x

Simplify the arithmetic:

3x-3=(x+9)-x

Group like terms:

3x-3=(x-x)+9

Simplify the arithmetic:

3x3=9

Add to both sides:

(3x-3)+3=9+3

Simplify the arithmetic:

3x=9+3

Simplify the arithmetic:

3x=12

Divide both sides by :

(3x)3=123

Simplify the fraction:

x=123

Find the greatest common factor of the numerator and denominator:

x=(4·3)(1·3)

Factor out and cancel the greatest common factor:

x=4

10 additional steps

(4x-3)=-(x+9)

Expand the parentheses:

(4x-3)=-x-9

Add to both sides:

(4x-3)+x=(-x-9)+x

Group like terms:

(4x+x)-3=(-x-9)+x

Simplify the arithmetic:

5x-3=(-x-9)+x

Group like terms:

5x-3=(-x+x)-9

Simplify the arithmetic:

5x3=9

Add to both sides:

(5x-3)+3=-9+3

Simplify the arithmetic:

5x=9+3

Simplify the arithmetic:

5x=6

Divide both sides by :

(5x)5=-65

Simplify the fraction:

x=-65

3. List the solutions

x=4,-65
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4x3|
y=|x+9|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.