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Solution - Absolute value equations

Exact form: x=-5,-911
x=-5 , -\frac{9}{11}
Decimal form: x=5,0.818
x=-5 , -0.818

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4x3|=|7x+12|
without the absolute value bars:

|x|=|y||4x3|=|7x+12|
x=+y(4x3)=(7x+12)
x=y(4x3)=(7x+12)
+x=y(4x3)=(7x+12)
x=y(4x3)=(7x+12)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4x3|=|7x+12|
x=+y , +x=y(4x3)=(7x+12)
x=y , x=y(4x3)=(7x+12)

2. Solve the two equations for x

13 additional steps

(4x-3)=(7x+12)

Subtract from both sides:

(4x-3)-7x=(7x+12)-7x

Group like terms:

(4x-7x)-3=(7x+12)-7x

Simplify the arithmetic:

-3x-3=(7x+12)-7x

Group like terms:

-3x-3=(7x-7x)+12

Simplify the arithmetic:

3x3=12

Add to both sides:

(-3x-3)+3=12+3

Simplify the arithmetic:

3x=12+3

Simplify the arithmetic:

3x=15

Divide both sides by :

(-3x)-3=15-3

Cancel out the negatives:

3x3=15-3

Simplify the fraction:

x=15-3

Move the negative sign from the denominator to the numerator:

x=-153

Find the greatest common factor of the numerator and denominator:

x=(-5·3)(1·3)

Factor out and cancel the greatest common factor:

x=5

10 additional steps

(4x-3)=-(7x+12)

Expand the parentheses:

(4x-3)=-7x-12

Add to both sides:

(4x-3)+7x=(-7x-12)+7x

Group like terms:

(4x+7x)-3=(-7x-12)+7x

Simplify the arithmetic:

11x-3=(-7x-12)+7x

Group like terms:

11x-3=(-7x+7x)-12

Simplify the arithmetic:

11x3=12

Add to both sides:

(11x-3)+3=-12+3

Simplify the arithmetic:

11x=12+3

Simplify the arithmetic:

11x=9

Divide both sides by :

(11x)11=-911

Simplify the fraction:

x=-911

3. List the solutions

x=-5,-911
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4x3|
y=|7x+12|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.