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Solution - Absolute value equations

Exact form: x=5,-23
x=5 , -\frac{2}{3}
Decimal form: x=5,0.667
x=5 , -0.667

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4x3|=|2x+7|
without the absolute value bars:

|x|=|y||4x3|=|2x+7|
x=+y(4x3)=(2x+7)
x=y(4x3)=(2x+7)
+x=y(4x3)=(2x+7)
x=y(4x3)=(2x+7)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4x3|=|2x+7|
x=+y , +x=y(4x3)=(2x+7)
x=y , x=y(4x3)=(2x+7)

2. Solve the two equations for x

11 additional steps

(4x-3)=(2x+7)

Subtract from both sides:

(4x-3)-2x=(2x+7)-2x

Group like terms:

(4x-2x)-3=(2x+7)-2x

Simplify the arithmetic:

2x-3=(2x+7)-2x

Group like terms:

2x-3=(2x-2x)+7

Simplify the arithmetic:

2x3=7

Add to both sides:

(2x-3)+3=7+3

Simplify the arithmetic:

2x=7+3

Simplify the arithmetic:

2x=10

Divide both sides by :

(2x)2=102

Simplify the fraction:

x=102

Find the greatest common factor of the numerator and denominator:

x=(5·2)(1·2)

Factor out and cancel the greatest common factor:

x=5

12 additional steps

(4x-3)=-(2x+7)

Expand the parentheses:

(4x-3)=-2x-7

Add to both sides:

(4x-3)+2x=(-2x-7)+2x

Group like terms:

(4x+2x)-3=(-2x-7)+2x

Simplify the arithmetic:

6x-3=(-2x-7)+2x

Group like terms:

6x-3=(-2x+2x)-7

Simplify the arithmetic:

6x3=7

Add to both sides:

(6x-3)+3=-7+3

Simplify the arithmetic:

6x=7+3

Simplify the arithmetic:

6x=4

Divide both sides by :

(6x)6=-46

Simplify the fraction:

x=-46

Find the greatest common factor of the numerator and denominator:

x=(-2·2)(3·2)

Factor out and cancel the greatest common factor:

x=-23

3. List the solutions

x=5,-23
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4x3|
y=|2x+7|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.