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Solution - Absolute value equations

Exact form: x=5,5
x=5 , 5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|4x20|+|3x15|=0

Add |3x15| to both sides of the equation:

|4x20|+|3x15||3x15|=|3x15|

Simplify the arithmetic

|4x20|=|3x15|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4x20|=|3x15|
without the absolute value bars:

|x|=|y||4x20|=|3x15|
x=+y(4x20)=(3x15)
x=y(4x20)=(3x15)
+x=y(4x20)=(3x15)
x=y(4x20)=(3x15)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4x20|=|3x15|
x=+y , +x=y(4x20)=(3x15)
x=y , x=y(4x20)=(3x15)

3. Solve the two equations for x

12 additional steps

(4x-20)=-(3x-15)

Expand the parentheses:

(4x-20)=-3x+15

Add to both sides:

(4x-20)+3x=(-3x+15)+3x

Group like terms:

(4x+3x)-20=(-3x+15)+3x

Simplify the arithmetic:

7x-20=(-3x+15)+3x

Group like terms:

7x-20=(-3x+3x)+15

Simplify the arithmetic:

7x20=15

Add to both sides:

(7x-20)+20=15+20

Simplify the arithmetic:

7x=15+20

Simplify the arithmetic:

7x=35

Divide both sides by :

(7x)7=357

Simplify the fraction:

x=357

Find the greatest common factor of the numerator and denominator:

x=(5·7)(1·7)

Factor out and cancel the greatest common factor:

x=5

8 additional steps

(4x-20)=-(-(3x-15))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(4x-20)=3x-15

Subtract from both sides:

(4x-20)-3x=(3x-15)-3x

Group like terms:

(4x-3x)-20=(3x-15)-3x

Simplify the arithmetic:

x-20=(3x-15)-3x

Group like terms:

x-20=(3x-3x)-15

Simplify the arithmetic:

x20=15

Add to both sides:

(x-20)+20=-15+20

Simplify the arithmetic:

x=15+20

Simplify the arithmetic:

x=5

4. List the solutions

x=5,5
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|4x20|
y=|3x15|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.