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Solution - Absolute value equations

Exact form: x=3,1
x=3 , -1

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4x2|=|x+7|
without the absolute value bars:

|x|=|y||4x2|=|x+7|
x=+y(4x2)=(x+7)
x=y(4x2)=(x+7)
+x=y(4x2)=(x+7)
x=y(4x2)=(x+7)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4x2|=|x+7|
x=+y , +x=y(4x2)=(x+7)
x=y , x=y(4x2)=(x+7)

2. Solve the two equations for x

11 additional steps

(4x-2)=(x+7)

Subtract from both sides:

(4x-2)-x=(x+7)-x

Group like terms:

(4x-x)-2=(x+7)-x

Simplify the arithmetic:

3x-2=(x+7)-x

Group like terms:

3x-2=(x-x)+7

Simplify the arithmetic:

3x2=7

Add to both sides:

(3x-2)+2=7+2

Simplify the arithmetic:

3x=7+2

Simplify the arithmetic:

3x=9

Divide both sides by :

(3x)3=93

Simplify the fraction:

x=93

Find the greatest common factor of the numerator and denominator:

x=(3·3)(1·3)

Factor out and cancel the greatest common factor:

x=3

11 additional steps

(4x-2)=-(x+7)

Expand the parentheses:

(4x-2)=-x-7

Add to both sides:

(4x-2)+x=(-x-7)+x

Group like terms:

(4x+x)-2=(-x-7)+x

Simplify the arithmetic:

5x-2=(-x-7)+x

Group like terms:

5x-2=(-x+x)-7

Simplify the arithmetic:

5x2=7

Add to both sides:

(5x-2)+2=-7+2

Simplify the arithmetic:

5x=7+2

Simplify the arithmetic:

5x=5

Divide both sides by :

(5x)5=-55

Simplify the fraction:

x=-55

Simplify the fraction:

x=1

3. List the solutions

x=3,1
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4x2|
y=|x+7|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.