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Solution - Absolute value equations

Exact form: x=-135,-913
x=-\frac{13}{5} , -\frac{9}{13}
Mixed number form: x=-235,-913
x=-2\frac{3}{5} , -\frac{9}{13}
Decimal form: x=2.6,0.692
x=-2.6 , -0.692

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4x2|=|9x+11|
without the absolute value bars:

|x|=|y||4x2|=|9x+11|
x=+y(4x2)=(9x+11)
x=y(4x2)=(9x+11)
+x=y(4x2)=(9x+11)
x=y(4x2)=(9x+11)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4x2|=|9x+11|
x=+y , +x=y(4x2)=(9x+11)
x=y , x=y(4x2)=(9x+11)

2. Solve the two equations for x

11 additional steps

(4x-2)=(9x+11)

Subtract from both sides:

(4x-2)-9x=(9x+11)-9x

Group like terms:

(4x-9x)-2=(9x+11)-9x

Simplify the arithmetic:

-5x-2=(9x+11)-9x

Group like terms:

-5x-2=(9x-9x)+11

Simplify the arithmetic:

5x2=11

Add to both sides:

(-5x-2)+2=11+2

Simplify the arithmetic:

5x=11+2

Simplify the arithmetic:

5x=13

Divide both sides by :

(-5x)-5=13-5

Cancel out the negatives:

5x5=13-5

Simplify the fraction:

x=13-5

Move the negative sign from the denominator to the numerator:

x=-135

10 additional steps

(4x-2)=-(9x+11)

Expand the parentheses:

(4x-2)=-9x-11

Add to both sides:

(4x-2)+9x=(-9x-11)+9x

Group like terms:

(4x+9x)-2=(-9x-11)+9x

Simplify the arithmetic:

13x-2=(-9x-11)+9x

Group like terms:

13x-2=(-9x+9x)-11

Simplify the arithmetic:

13x2=11

Add to both sides:

(13x-2)+2=-11+2

Simplify the arithmetic:

13x=11+2

Simplify the arithmetic:

13x=9

Divide both sides by :

(13x)13=-913

Simplify the fraction:

x=-913

3. List the solutions

x=-135,-913
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4x2|
y=|9x+11|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.