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Solution - Absolute value equations

Exact form: x=12
x=\frac{1}{2}
Decimal form: x=0.5
x=0.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4x10|=2|2x+3|
without the absolute value bars:

|x|=|y||4x10|=2|2x+3|
x=+y(4x10)=2(2x+3)
x=y(4x10)=2((2x+3))
+x=y(4x10)=2(2x+3)
x=y(4x10)=2(2x+3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4x10|=2|2x+3|
x=+y , +x=y(4x10)=2(2x+3)
x=y , x=y(4x10)=2((2x+3))

2. Solve the two equations for x

8 additional steps

(4x-10)=2·(2x+3)

Expand the parentheses:

(4x-10)=2·2x+2·3

Multiply the coefficients:

(4x-10)=4x+2·3

Simplify the arithmetic:

(4x-10)=4x+6

Subtract from both sides:

(4x-10)-4x=(4x+6)-4x

Group like terms:

(4x-4x)-10=(4x+6)-4x

Simplify the arithmetic:

-10=(4x+6)-4x

Group like terms:

-10=(4x-4x)+6

Simplify the arithmetic:

10=6

The statement is false:

10=6

The equation is false so it has no solution.

15 additional steps

(4x-10)=2·(-(2x+3))

Expand the parentheses:

(4x-10)=2·(-2x-3)

Expand the parentheses:

(4x-10)=2·-2x+2·-3

Multiply the coefficients:

(4x-10)=-4x+2·-3

Simplify the arithmetic:

(4x-10)=-4x-6

Add to both sides:

(4x-10)+4x=(-4x-6)+4x

Group like terms:

(4x+4x)-10=(-4x-6)+4x

Simplify the arithmetic:

8x-10=(-4x-6)+4x

Group like terms:

8x-10=(-4x+4x)-6

Simplify the arithmetic:

8x10=6

Add to both sides:

(8x-10)+10=-6+10

Simplify the arithmetic:

8x=6+10

Simplify the arithmetic:

8x=4

Divide both sides by :

(8x)8=48

Simplify the fraction:

x=48

Find the greatest common factor of the numerator and denominator:

x=(1·4)(2·4)

Factor out and cancel the greatest common factor:

x=12

3. Graph

Each line represents the function of one side of the equation:
y=|4x10|
y=2|2x+3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.