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Solution - Absolute value equations

Exact form: x=1,25
x=1 , \frac{2}{5}
Decimal form: x=1,0.4
x=1 , 0.4

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4x1|=|6x3|
without the absolute value bars:

|x|=|y||4x1|=|6x3|
x=+y(4x1)=(6x3)
x=y(4x1)=(6x3)
+x=y(4x1)=(6x3)
x=y(4x1)=(6x3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4x1|=|6x3|
x=+y , +x=y(4x1)=(6x3)
x=y , x=y(4x1)=(6x3)

2. Solve the two equations for x

12 additional steps

(4x-1)=(6x-3)

Subtract from both sides:

(4x-1)-6x=(6x-3)-6x

Group like terms:

(4x-6x)-1=(6x-3)-6x

Simplify the arithmetic:

-2x-1=(6x-3)-6x

Group like terms:

-2x-1=(6x-6x)-3

Simplify the arithmetic:

2x1=3

Add to both sides:

(-2x-1)+1=-3+1

Simplify the arithmetic:

2x=3+1

Simplify the arithmetic:

2x=2

Divide both sides by :

(-2x)-2=-2-2

Cancel out the negatives:

2x2=-2-2

Simplify the fraction:

x=-2-2

Cancel out the negatives:

x=22

Simplify the fraction:

x=1

12 additional steps

(4x-1)=-(6x-3)

Expand the parentheses:

(4x-1)=-6x+3

Add to both sides:

(4x-1)+6x=(-6x+3)+6x

Group like terms:

(4x+6x)-1=(-6x+3)+6x

Simplify the arithmetic:

10x-1=(-6x+3)+6x

Group like terms:

10x-1=(-6x+6x)+3

Simplify the arithmetic:

10x1=3

Add to both sides:

(10x-1)+1=3+1

Simplify the arithmetic:

10x=3+1

Simplify the arithmetic:

10x=4

Divide both sides by :

(10x)10=410

Simplify the fraction:

x=410

Find the greatest common factor of the numerator and denominator:

x=(2·2)(5·2)

Factor out and cancel the greatest common factor:

x=25

3. List the solutions

x=1,25
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4x1|
y=|6x3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.