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Solution - Absolute value equations

Exact form: x=2,-13
x=2 , -\frac{1}{3}
Decimal form: x=2,0.333
x=2 , -0.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4x1|=|2x+3|
without the absolute value bars:

|x|=|y||4x1|=|2x+3|
x=+y(4x1)=(2x+3)
x=y(4x1)=(2x+3)
+x=y(4x1)=(2x+3)
x=y(4x1)=(2x+3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4x1|=|2x+3|
x=+y , +x=y(4x1)=(2x+3)
x=y , x=y(4x1)=(2x+3)

2. Solve the two equations for x

11 additional steps

(4x-1)=(2x+3)

Subtract from both sides:

(4x-1)-2x=(2x+3)-2x

Group like terms:

(4x-2x)-1=(2x+3)-2x

Simplify the arithmetic:

2x-1=(2x+3)-2x

Group like terms:

2x-1=(2x-2x)+3

Simplify the arithmetic:

2x1=3

Add to both sides:

(2x-1)+1=3+1

Simplify the arithmetic:

2x=3+1

Simplify the arithmetic:

2x=4

Divide both sides by :

(2x)2=42

Simplify the fraction:

x=42

Find the greatest common factor of the numerator and denominator:

x=(2·2)(1·2)

Factor out and cancel the greatest common factor:

x=2

12 additional steps

(4x-1)=-(2x+3)

Expand the parentheses:

(4x-1)=-2x-3

Add to both sides:

(4x-1)+2x=(-2x-3)+2x

Group like terms:

(4x+2x)-1=(-2x-3)+2x

Simplify the arithmetic:

6x-1=(-2x-3)+2x

Group like terms:

6x-1=(-2x+2x)-3

Simplify the arithmetic:

6x1=3

Add to both sides:

(6x-1)+1=-3+1

Simplify the arithmetic:

6x=3+1

Simplify the arithmetic:

6x=2

Divide both sides by :

(6x)6=-26

Simplify the fraction:

x=-26

Find the greatest common factor of the numerator and denominator:

x=(-1·2)(3·2)

Factor out and cancel the greatest common factor:

x=-13

3. List the solutions

x=2,-13
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4x1|
y=|2x+3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.