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Solution - Absolute value equations

Exact form: x=2,23
x=2 , \frac{2}{3}
Decimal form: x=2,0.667
x=2 , 0.667

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|4x4|2|x|=0

Add 2|x| to both sides of the equation:

|4x4|2|x|+2|x|=2|x|

Simplify the arithmetic

|4x4|=2|x|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4x4|=2|x|
without the absolute value bars:

|x|=|y||4x4|=2|x|
x=+y(4x4)=2(x)
x=y(4x4)=2((x))
+x=y(4x4)=2(x)
x=y(4x4)=2(x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4x4|=2|x|
x=+y , +x=y(4x4)=2(x)
x=y , x=y(4x4)=2((x))

3. Solve the two equations for x

10 additional steps

(4x-4)=2x

Subtract from both sides:

(4x-4)-2x=(2x)-2x

Group like terms:

(4x-2x)-4=(2x)-2x

Simplify the arithmetic:

2x-4=(2x)-2x

Simplify the arithmetic:

2x4=0

Add to both sides:

(2x-4)+4=0+4

Simplify the arithmetic:

2x=0+4

Simplify the arithmetic:

2x=4

Divide both sides by :

(2x)2=42

Simplify the fraction:

x=42

Find the greatest common factor of the numerator and denominator:

x=(2·2)(1·2)

Factor out and cancel the greatest common factor:

x=2

12 additional steps

(4x-4)=2·-x

Group like terms:

(4x-4)=(2·-1)x

Multiply the coefficients:

(4x-4)=-2x

Add to both sides:

(4x-4)+2x=(-2x)+2x

Group like terms:

(4x+2x)-4=(-2x)+2x

Simplify the arithmetic:

6x-4=(-2x)+2x

Simplify the arithmetic:

6x4=0

Add to both sides:

(6x-4)+4=0+4

Simplify the arithmetic:

6x=0+4

Simplify the arithmetic:

6x=4

Divide both sides by :

(6x)6=46

Simplify the fraction:

x=46

Find the greatest common factor of the numerator and denominator:

x=(2·2)(3·2)

Factor out and cancel the greatest common factor:

x=23

4. List the solutions

x=2,23
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|4x4|
y=2|x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.