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Solution - Absolute value equations

Exact form: x=-13,15
x=-\frac{1}{3} , 15
Decimal form: x=0.333,15
x=-0.333 , 15

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4x+9|=|5x+6|
without the absolute value bars:

|x|=|y||4x+9|=|5x+6|
x=+y(4x+9)=(5x+6)
x=y(4x+9)=(5x+6)
+x=y(4x+9)=(5x+6)
x=y(4x+9)=(5x+6)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4x+9|=|5x+6|
x=+y , +x=y(4x+9)=(5x+6)
x=y , x=y(4x+9)=(5x+6)

2. Solve the two equations for x

11 additional steps

(4x+9)=(-5x+6)

Add to both sides:

(4x+9)+5x=(-5x+6)+5x

Group like terms:

(4x+5x)+9=(-5x+6)+5x

Simplify the arithmetic:

9x+9=(-5x+6)+5x

Group like terms:

9x+9=(-5x+5x)+6

Simplify the arithmetic:

9x+9=6

Subtract from both sides:

(9x+9)-9=6-9

Simplify the arithmetic:

9x=69

Simplify the arithmetic:

9x=3

Divide both sides by :

(9x)9=-39

Simplify the fraction:

x=-39

Find the greatest common factor of the numerator and denominator:

x=(-1·3)(3·3)

Factor out and cancel the greatest common factor:

x=-13

11 additional steps

(4x+9)=-(-5x+6)

Expand the parentheses:

(4x+9)=5x-6

Subtract from both sides:

(4x+9)-5x=(5x-6)-5x

Group like terms:

(4x-5x)+9=(5x-6)-5x

Simplify the arithmetic:

-x+9=(5x-6)-5x

Group like terms:

-x+9=(5x-5x)-6

Simplify the arithmetic:

x+9=6

Subtract from both sides:

(-x+9)-9=-6-9

Simplify the arithmetic:

x=69

Simplify the arithmetic:

x=15

Multiply both sides by :

-x·-1=-15·-1

Remove the one(s):

x=-15·-1

Simplify the arithmetic:

x=15

3. List the solutions

x=-13,15
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4x+9|
y=|5x+6|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.