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Solution - Absolute value equations

Exact form: x=-1,-53
x=-1 , -\frac{5}{3}
Mixed number form: x=-1,-123
x=-1 , -1\frac{2}{3}
Decimal form: x=1,1.667
x=-1 , -1.667

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4x+6|=|2x+4|
without the absolute value bars:

|x|=|y||4x+6|=|2x+4|
x=+y(4x+6)=(2x+4)
x=y(4x+6)=(2x+4)
+x=y(4x+6)=(2x+4)
x=y(4x+6)=(2x+4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4x+6|=|2x+4|
x=+y , +x=y(4x+6)=(2x+4)
x=y , x=y(4x+6)=(2x+4)

2. Solve the two equations for x

10 additional steps

(4x+6)=(2x+4)

Subtract from both sides:

(4x+6)-2x=(2x+4)-2x

Group like terms:

(4x-2x)+6=(2x+4)-2x

Simplify the arithmetic:

2x+6=(2x+4)-2x

Group like terms:

2x+6=(2x-2x)+4

Simplify the arithmetic:

2x+6=4

Subtract from both sides:

(2x+6)-6=4-6

Simplify the arithmetic:

2x=46

Simplify the arithmetic:

2x=2

Divide both sides by :

(2x)2=-22

Simplify the fraction:

x=-22

Simplify the fraction:

x=1

12 additional steps

(4x+6)=-(2x+4)

Expand the parentheses:

(4x+6)=-2x-4

Add to both sides:

(4x+6)+2x=(-2x-4)+2x

Group like terms:

(4x+2x)+6=(-2x-4)+2x

Simplify the arithmetic:

6x+6=(-2x-4)+2x

Group like terms:

6x+6=(-2x+2x)-4

Simplify the arithmetic:

6x+6=4

Subtract from both sides:

(6x+6)-6=-4-6

Simplify the arithmetic:

6x=46

Simplify the arithmetic:

6x=10

Divide both sides by :

(6x)6=-106

Simplify the fraction:

x=-106

Find the greatest common factor of the numerator and denominator:

x=(-5·2)(3·2)

Factor out and cancel the greatest common factor:

x=-53

3. List the solutions

x=-1,-53
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4x+6|
y=|2x+4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.