Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=23,-417
x=\frac{2}{3} , -\frac{4}{17}
Decimal form: x=0.667,0.235
x=0.667 , -0.235

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4x+5|=|13x1|
without the absolute value bars:

|x|=|y||4x+5|=|13x1|
x=+y(4x+5)=(13x1)
x=y(4x+5)=(13x1)
+x=y(4x+5)=(13x1)
x=y(4x+5)=(13x1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4x+5|=|13x1|
x=+y , +x=y(4x+5)=(13x1)
x=y , x=y(4x+5)=(13x1)

2. Solve the two equations for x

13 additional steps

(4x+5)=(13x-1)

Subtract from both sides:

(4x+5)-13x=(13x-1)-13x

Group like terms:

(4x-13x)+5=(13x-1)-13x

Simplify the arithmetic:

-9x+5=(13x-1)-13x

Group like terms:

-9x+5=(13x-13x)-1

Simplify the arithmetic:

9x+5=1

Subtract from both sides:

(-9x+5)-5=-1-5

Simplify the arithmetic:

9x=15

Simplify the arithmetic:

9x=6

Divide both sides by :

(-9x)-9=-6-9

Cancel out the negatives:

9x9=-6-9

Simplify the fraction:

x=-6-9

Cancel out the negatives:

x=69

Find the greatest common factor of the numerator and denominator:

x=(2·3)(3·3)

Factor out and cancel the greatest common factor:

x=23

10 additional steps

(4x+5)=-(13x-1)

Expand the parentheses:

(4x+5)=-13x+1

Add to both sides:

(4x+5)+13x=(-13x+1)+13x

Group like terms:

(4x+13x)+5=(-13x+1)+13x

Simplify the arithmetic:

17x+5=(-13x+1)+13x

Group like terms:

17x+5=(-13x+13x)+1

Simplify the arithmetic:

17x+5=1

Subtract from both sides:

(17x+5)-5=1-5

Simplify the arithmetic:

17x=15

Simplify the arithmetic:

17x=4

Divide both sides by :

(17x)17=-417

Simplify the fraction:

x=-417

3. List the solutions

x=23,-417
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4x+5|
y=|13x1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.