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Solution - Absolute value equations

Exact form: x=1,-35
x=1 , -\frac{3}{5}
Decimal form: x=1,0.6
x=1 , -0.6

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4x+4|=|6x+2|
without the absolute value bars:

|x|=|y||4x+4|=|6x+2|
x=+y(4x+4)=(6x+2)
x=y(4x+4)=(6x+2)
+x=y(4x+4)=(6x+2)
x=y(4x+4)=(6x+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4x+4|=|6x+2|
x=+y , +x=y(4x+4)=(6x+2)
x=y , x=y(4x+4)=(6x+2)

2. Solve the two equations for x

12 additional steps

(4x+4)=(6x+2)

Subtract from both sides:

(4x+4)-6x=(6x+2)-6x

Group like terms:

(4x-6x)+4=(6x+2)-6x

Simplify the arithmetic:

-2x+4=(6x+2)-6x

Group like terms:

-2x+4=(6x-6x)+2

Simplify the arithmetic:

2x+4=2

Subtract from both sides:

(-2x+4)-4=2-4

Simplify the arithmetic:

2x=24

Simplify the arithmetic:

2x=2

Divide both sides by :

(-2x)-2=-2-2

Cancel out the negatives:

2x2=-2-2

Simplify the fraction:

x=-2-2

Cancel out the negatives:

x=22

Simplify the fraction:

x=1

12 additional steps

(4x+4)=-(6x+2)

Expand the parentheses:

(4x+4)=-6x-2

Add to both sides:

(4x+4)+6x=(-6x-2)+6x

Group like terms:

(4x+6x)+4=(-6x-2)+6x

Simplify the arithmetic:

10x+4=(-6x-2)+6x

Group like terms:

10x+4=(-6x+6x)-2

Simplify the arithmetic:

10x+4=2

Subtract from both sides:

(10x+4)-4=-2-4

Simplify the arithmetic:

10x=24

Simplify the arithmetic:

10x=6

Divide both sides by :

(10x)10=-610

Simplify the fraction:

x=-610

Find the greatest common factor of the numerator and denominator:

x=(-3·2)(5·2)

Factor out and cancel the greatest common factor:

x=-35

3. List the solutions

x=1,-35
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4x+4|
y=|6x+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.