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Solution - Absolute value equations

Exact form: x=-43,-25
x=-\frac{4}{3} , -\frac{2}{5}
Mixed number form: x=-113,-25
x=-1\frac{1}{3} , -\frac{2}{5}
Decimal form: x=1.333,0.4
x=-1.333 , -0.4

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4x+3|=|x1|
without the absolute value bars:

|x|=|y||4x+3|=|x1|
x=+y(4x+3)=(x1)
x=y(4x+3)=(x1)
+x=y(4x+3)=(x1)
x=y(4x+3)=(x1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4x+3|=|x1|
x=+y , +x=y(4x+3)=(x1)
x=y , x=y(4x+3)=(x1)

2. Solve the two equations for x

9 additional steps

(4x+3)=(x-1)

Subtract from both sides:

(4x+3)-x=(x-1)-x

Group like terms:

(4x-x)+3=(x-1)-x

Simplify the arithmetic:

3x+3=(x-1)-x

Group like terms:

3x+3=(x-x)-1

Simplify the arithmetic:

3x+3=1

Subtract from both sides:

(3x+3)-3=-1-3

Simplify the arithmetic:

3x=13

Simplify the arithmetic:

3x=4

Divide both sides by :

(3x)3=-43

Simplify the fraction:

x=-43

10 additional steps

(4x+3)=-(x-1)

Expand the parentheses:

(4x+3)=-x+1

Add to both sides:

(4x+3)+x=(-x+1)+x

Group like terms:

(4x+x)+3=(-x+1)+x

Simplify the arithmetic:

5x+3=(-x+1)+x

Group like terms:

5x+3=(-x+x)+1

Simplify the arithmetic:

5x+3=1

Subtract from both sides:

(5x+3)-3=1-3

Simplify the arithmetic:

5x=13

Simplify the arithmetic:

5x=2

Divide both sides by :

(5x)5=-25

Simplify the fraction:

x=-25

3. List the solutions

x=-43,-25
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4x+3|
y=|x1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.