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Solution - Absolute value equations

Exact form: x=-74
x=-\frac{7}{4}
Mixed number form: x=-134
x=-1\frac{3}{4}
Decimal form: x=1.75
x=-1.75

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4x+23|=|4x9|
without the absolute value bars:

|x|=|y||4x+23|=|4x9|
x=+y(4x+23)=(4x9)
x=y(4x+23)=(4x9)
+x=y(4x+23)=(4x9)
x=y(4x+23)=(4x9)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4x+23|=|4x9|
x=+y , +x=y(4x+23)=(4x9)
x=y , x=y(4x+23)=(4x9)

2. Solve the two equations for x

5 additional steps

(4x+23)=(4x-9)

Subtract from both sides:

(4x+23)-4x=(4x-9)-4x

Group like terms:

(4x-4x)+23=(4x-9)-4x

Simplify the arithmetic:

23=(4x-9)-4x

Group like terms:

23=(4x-4x)-9

Simplify the arithmetic:

23=9

The statement is false:

23=9

The equation is false so it has no solution.

12 additional steps

(4x+23)=-(4x-9)

Expand the parentheses:

(4x+23)=-4x+9

Add to both sides:

(4x+23)+4x=(-4x+9)+4x

Group like terms:

(4x+4x)+23=(-4x+9)+4x

Simplify the arithmetic:

8x+23=(-4x+9)+4x

Group like terms:

8x+23=(-4x+4x)+9

Simplify the arithmetic:

8x+23=9

Subtract from both sides:

(8x+23)-23=9-23

Simplify the arithmetic:

8x=923

Simplify the arithmetic:

8x=14

Divide both sides by :

(8x)8=-148

Simplify the fraction:

x=-148

Find the greatest common factor of the numerator and denominator:

x=(-7·2)(4·2)

Factor out and cancel the greatest common factor:

x=-74

3. Graph

Each line represents the function of one side of the equation:
y=|4x+23|
y=|4x9|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.