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Solution - Absolute value equations

Exact form: x=54,14
x=\frac{5}{4} , \frac{1}{4}
Mixed number form: x=114,14
x=1\frac{1}{4} , \frac{1}{4}
Decimal form: x=1.25,0.25
x=1.25 , 0.25

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4x+1|=|8x4|
without the absolute value bars:

|x|=|y||4x+1|=|8x4|
x=+y(4x+1)=(8x4)
x=y(4x+1)=(8x4)
+x=y(4x+1)=(8x4)
x=y(4x+1)=(8x4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4x+1|=|8x4|
x=+y , +x=y(4x+1)=(8x4)
x=y , x=y(4x+1)=(8x4)

2. Solve the two equations for x

11 additional steps

(4x+1)=(8x-4)

Subtract from both sides:

(4x+1)-8x=(8x-4)-8x

Group like terms:

(4x-8x)+1=(8x-4)-8x

Simplify the arithmetic:

-4x+1=(8x-4)-8x

Group like terms:

-4x+1=(8x-8x)-4

Simplify the arithmetic:

4x+1=4

Subtract from both sides:

(-4x+1)-1=-4-1

Simplify the arithmetic:

4x=41

Simplify the arithmetic:

4x=5

Divide both sides by :

(-4x)-4=-5-4

Cancel out the negatives:

4x4=-5-4

Simplify the fraction:

x=-5-4

Cancel out the negatives:

x=54

12 additional steps

(4x+1)=-(8x-4)

Expand the parentheses:

(4x+1)=-8x+4

Add to both sides:

(4x+1)+8x=(-8x+4)+8x

Group like terms:

(4x+8x)+1=(-8x+4)+8x

Simplify the arithmetic:

12x+1=(-8x+4)+8x

Group like terms:

12x+1=(-8x+8x)+4

Simplify the arithmetic:

12x+1=4

Subtract from both sides:

(12x+1)-1=4-1

Simplify the arithmetic:

12x=41

Simplify the arithmetic:

12x=3

Divide both sides by :

(12x)12=312

Simplify the fraction:

x=312

Find the greatest common factor of the numerator and denominator:

x=(1·3)(4·3)

Factor out and cancel the greatest common factor:

x=14

3. List the solutions

x=54,14
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4x+1|
y=|8x4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.