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Solution - Absolute value equations

Exact form: w=-43,-65
w=-\frac{4}{3} , -\frac{6}{5}
Mixed number form: w=-113,-115
w=-1\frac{1}{3} , -1\frac{1}{5}
Decimal form: w=1.333,1.2
w=-1.333 , -1.2

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4w+5|=|w+1|
without the absolute value bars:

|x|=|y||4w+5|=|w+1|
x=+y(4w+5)=(w+1)
x=y(4w+5)=(w+1)
+x=y(4w+5)=(w+1)
x=y(4w+5)=(w+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4w+5|=|w+1|
x=+y , +x=y(4w+5)=(w+1)
x=y , x=y(4w+5)=(w+1)

2. Solve the two equations for w

9 additional steps

(4w+5)=(w+1)

Subtract from both sides:

(4w+5)-w=(w+1)-w

Group like terms:

(4w-w)+5=(w+1)-w

Simplify the arithmetic:

3w+5=(w+1)-w

Group like terms:

3w+5=(w-w)+1

Simplify the arithmetic:

3w+5=1

Subtract from both sides:

(3w+5)-5=1-5

Simplify the arithmetic:

3w=15

Simplify the arithmetic:

3w=4

Divide both sides by :

(3w)3=-43

Simplify the fraction:

w=-43

10 additional steps

(4w+5)=-(w+1)

Expand the parentheses:

(4w+5)=-w-1

Add to both sides:

(4w+5)+w=(-w-1)+w

Group like terms:

(4w+w)+5=(-w-1)+w

Simplify the arithmetic:

5w+5=(-w-1)+w

Group like terms:

5w+5=(-w+w)-1

Simplify the arithmetic:

5w+5=1

Subtract from both sides:

(5w+5)-5=-1-5

Simplify the arithmetic:

5w=15

Simplify the arithmetic:

5w=6

Divide both sides by :

(5w)5=-65

Simplify the fraction:

w=-65

3. List the solutions

w=-43,-65
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4w+5|
y=|w+1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.