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Solution - Absolute value equations

Exact form: w=-4,13
w=-4 , \frac{1}{3}
Decimal form: w=4,0.333
w=-4 , 0.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4w+3|=|2w5|
without the absolute value bars:

|x|=|y||4w+3|=|2w5|
x=+y(4w+3)=(2w5)
x=y(4w+3)=(2w5)
+x=y(4w+3)=(2w5)
x=y(4w+3)=(2w5)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4w+3|=|2w5|
x=+y , +x=y(4w+3)=(2w5)
x=y , x=y(4w+3)=(2w5)

2. Solve the two equations for w

11 additional steps

(4w+3)=(2w-5)

Subtract from both sides:

(4w+3)-2w=(2w-5)-2w

Group like terms:

(4w-2w)+3=(2w-5)-2w

Simplify the arithmetic:

2w+3=(2w-5)-2w

Group like terms:

2w+3=(2w-2w)-5

Simplify the arithmetic:

2w+3=5

Subtract from both sides:

(2w+3)-3=-5-3

Simplify the arithmetic:

2w=53

Simplify the arithmetic:

2w=8

Divide both sides by :

(2w)2=-82

Simplify the fraction:

w=-82

Find the greatest common factor of the numerator and denominator:

w=(-4·2)(1·2)

Factor out and cancel the greatest common factor:

w=4

12 additional steps

(4w+3)=-(2w-5)

Expand the parentheses:

(4w+3)=-2w+5

Add to both sides:

(4w+3)+2w=(-2w+5)+2w

Group like terms:

(4w+2w)+3=(-2w+5)+2w

Simplify the arithmetic:

6w+3=(-2w+5)+2w

Group like terms:

6w+3=(-2w+2w)+5

Simplify the arithmetic:

6w+3=5

Subtract from both sides:

(6w+3)-3=5-3

Simplify the arithmetic:

6w=53

Simplify the arithmetic:

6w=2

Divide both sides by :

(6w)6=26

Simplify the fraction:

w=26

Find the greatest common factor of the numerator and denominator:

w=(1·2)(3·2)

Factor out and cancel the greatest common factor:

w=13

3. List the solutions

w=-4,13
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4w+3|
y=|2w5|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.